Tabla de función de Airy en coordenadas polares.
Componentes de desplazamiento.
| f | 2G ur | 2G uq | |
| (k=0) | |||
| r2 | (k-1)r | 0 | |
| r2lnr | (k-1)r lnr - r | (k+1)rq | |
| lnr | -1/r | 0 | |
| q | 0 | -1/r | |
| (k=1) | |||
| r3cosq | (k-2)r2cosq | (k+2)r2senq | |
| rq senq | { (k-1)q senq - cosq + (k+1)lnrcosq }/2 | { (k-1)q cosq - senq - (k+1)lnrsenq }/2 | |
| r lnr cosq | { (k+1)q senq - cosq + (k-1)lnrcosq }/2 | { (k+1)q cosq - senq - (k-1)lnrsenq }/2 | |
| r-1cosq | r-2senq | r-2senq | |
| r3senq | (k-2)r2senq | -(k+2)r2cosq | |
| rq cosq | { (k-1)q cosq + senq - (k+1)lnrsenq }/2 | { -(k-1)q senq - cosq - (k+1)lnrcosq }/2 | |
| r lnr senq | { -(k+1)q cosq - senq + (k-1)lnrsenq }/2 | { (k+1)q senq + cosq + (k-1)lnrcosq }/2 | |
| r-1senq | r-2senq | -r-2senq | |
| (k=n) | |||
| rn+2 cosnq | (k-n-1)rn+1cos nq | (k+n+1)rn+1sen nq | |
| r-n+2 cosnq | (k+n-1)r-n+1cos nq | -(k-n+1)r-n+1sen nq | |
| rn cosnq | -nrn-1cos nq | nrn-1sen nq | |
| r-n cosnq | nr-n-1cos nq | nr-n-1sen nq | |
| rn+2 sennq | (k-n-1)rn+1sen nq | -(k+n+1)rn+1cos nq | |
| r-n+2 sennq | (k+n-1)r-n+1sen nq | (k-n+1)r-n+1cos nq | |
| rn sennq | -nrn-1sen nq | -nrn-1cos nq | |
| r-n sennq | nr-n-1sen nq | -nr-n-1cos nq | |
| _ | |||
| Deformación plana: k=3-4n | Tensión plana: k=(3-n)/(1+n) | ||
Los desplazamientos pueden incluir además un movimiento de sólido rígido.